sci.physics.particle

wrote in message
news:57700d87-ac88-4cae-8e42-08b0be809268@i29g2000prf.googlegroups.com...
On Mar 6, 9:19 am, "Androcles" wrote:
> "PD" wrote in message
>
> news:d25d5e8d-69e8-4208-bf8e-0fd1a797767e@n58g2000hsf.googlegroups.com...
> On Mar 6, 9:38 am, The Ghost In The Machine
>
>
>
>
>
> wrote:
> > In sci.physics.relativity, Eric Gisse
> >
> > wrote
> > on Thu, 6 Mar 2008 06:50:41 -0800 (PST)
> > <2b831503-d191-4816-9c13-99a0eed97...@s8g2000prg.googlegroups.com>:
>
> > > On Mar 5, 9:55 pm, Koobee Wublee wrote:
> > >> On Mar 4, 6:03 pm, carlip-nos...@physics.ucdavis.edu wrote:
>
> > >> > I suggest that you try for a graceful retreat.
>
> > >> Well, I found a mistake in the boundary condition. As you have
> > >> suggested, I will execute a graceful retreat this time. In doing so,
> > >> my instinct might still be correct about any high-speed particle
> > >> having a discontinuity as its speed goes to the speed of light.
>
> > > My god your arrogance is astounding. DO THE COMPUTATION.
>
> > What math would you have him do? ;-) There is indeed a
> > discontinuity in the SR energy equation
>
> > E = m c^2 / sqrt(1-v^2/c^2)
>
> > Going through infinity to become imaginary energy sounds like
> > a pretty big discontinuity to me....
>
> | There's no going *through* infinity. There is an *approach* to
> | infinity. A function that has an infinite asymptote is not
> | discontinuous.
>
> y = tan(x) for x = 0 to pi has no discontinuity at pi/2?
> Why yes, yes it does.

| Graph it nitwit.

| tan pi = .054886...
| tan pi/2 = .027422...
| tan pi/100 = .0005483...
| tan pi/1000 = .00005483...

HAHAHAHA!

Try pressing the radians button on your calculator, fuckwit,
or entering 180 degrees for pi radians.

tan 180 degrees = 0
tan pi radians = 0
tan 90 degrees = ????
tan pi/2 radians = ????

What a dumbfuck, calling me nitwit!