microsoft.public.word.vba.general

Okay, I found that particular problem. It was the Spanish list delimiter. For
some reason the Range.Find function is sensitive to the list delimiter. The
code

.Text = "[0-9]{1;2}.^t

works because I use ";" as a list separator rather than ","

I can also determine the application.international(wdListSeparator) and use
that in an If structure to offer two different Range.Find statements.

But there must be more information on preparing code for international use.

Any suggestions?

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Windows XP, Word 2000